rec.autos.simulators

because the wheel is stopped by the ground and so don't have any vertical
acceleration/speed. In my model the tire have no weight, only angular inertia.

--
Sebastien TIXIER - Game Developer
Dynamics and Car Physics
http://www.racesimcentral.net/
GPLRank Normal:-42.98 Monster:-117.44

  You said you've got 55% load on the front tires.  You're using Beckman's
approach to Pacejka, so you have tire load sensitivity (degradation in mu with
increasing load) included?  If not, that might help a little.  Otherwise, with
so much load on the front end, perhaps you simply need less grippy tires on the
front.  

  As I mentioned earlier, my tire model is the worst of the ras bunch, but the
car handles just great IMO.  My camber changes don't effect forces yet and I've
got no load sensitivity, but it seems easier to drive than what you've been
describing regardless, so I doubt that's the problem you're having.  With 55%
load on the fronts and identical tires all the way around, you'll generate more
lateral force at the front than the rear and should be getting lots of
oversteer.  Perhaps you might try lowering the grip at the front somewhat.  It
seems that most cars (not sure about a '66 Charger) have bigger tires at the
rear than front anyway.

  If they had the same tires all the way around in real life, then it's
possible the camber gradient  would be to blame.  I think most production cars
(even high performance) get positive camber at the front outside wheel when
cornering hard, which lowers front end grip in an attempt to keep the handling
understeer.  

Todd Wasson
---
Performance Simulations
Drag Racing and Top Speed Prediction
Software
http://PerformanceSimulations.Com

-Gregor

maybe you try to do a joke in french, but your sentence is completly
incomprehensible ... maybe,err, certainly because my english sentence
was also incomprehensible ;o))))))

what did you want to say  ? "And you sebastien ?" ??

if so the write sentence in french is ...

"Et toi Sebastien ?"

 With 55%

But more lateral force on the front than the rear doesn't necessarily mean
that the torque produced by the front tyres will be greater than the torque
produced at the rear. Converting force to torque involves a cross product of
the force direction with the vector from the force position to the COM.
Since the front tyre will be turned slightly, this will produce less torque
than if it were aligned with the car's main axis.

Nah, it was just a reference to 'Et tu Brutus', which I used as I am
guilty of doing the same approximation (that guarantees good stability)
myself. :)

I wouldn't even dare to try typing French! ;)

Greetings,

-Gregor

 "I tu brutus"  ...

but maybe we had to continue ond rec.latin.qutation ;o)))))

-Gregor

So my first impression was the good one, i didn't understand anything !

What the meaning of "Et tu Brutus" ???

|  "I tu brutus"  ...

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Isn't that almost exactly the same?

Ruud van Gaal
Free car sim  : http://www.marketgraph.nl/gallery/racer/
Pencil art    : http://www.marketgraph.nl/gallery/

| Damn ! :o)
| So my first impression was the good one, i didn't understand anything !
| What the meaning of "Et tu Brutus" ???

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|
| "You too, Brutus" ?
| (Uttered by Caesar as he was stabbed to death according to Shakespeare)
| --
|   -asbjxrn

| > Damn ! :o)
| >
| > So my first impression was the good one, i didn't understand anything !
| >
| > What the meaning of "Et tu Brutus" ???

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