rec.autos.simulators

A new demo of my simulator

J. Todd Wass

A new demo of my simulator

by J. Todd Wass » Sun, 10 Feb 2002 09:20:58

  "Engine braking" in the context Ruud, Jonny, and myself are speaking of is a
torque, nothing else.  

The "rate at which the engine slows down" from this engine braking torque is
dependent on the engine braking torque and the mass combined (more
specifically, the polar moment of inertia of the engine/flywheel, which is
basically how massive it is with weight and size combined.)

As Ruud said:
Engine_Deceleration = Torque / Rotation_Inertia

Todd Wasson
---
Performance Simulations
Drag Racing and Top Speed Prediction
Software
http://www.racesimcentral.net/

My little car sim screenshots:
http://www.racesimcentral.net/

J. Todd Wass

A new demo of my simulator

by J. Todd Wass » Sun, 10 Feb 2002 09:36:31

  I'm afraid he's exactly right, rrevved.  I think you may not be aware that
Jonny is speaking of two different things seperately here, where it sounds like
you might be combining them in one concept, although mathematically, they are
seperate things.  The steady state torque the engine produces has nothing to do
with the mass of the engine.  Unless perhaps, you were looking at the
acceleration *between* power strokes of the engine, but that's irrevelant to
the point Jonny's trying to make here, I believe.  

 Increasing the mass of the engine causes the engine to accelerate/decelerate
more slowly:

Rotational_Acceleration = Torque / PM_Inertia

  The *torque* in this equation, is not dependent on the engine's mass..  But
rather, the acceleration is dependent on both the torque and the mass.  I
suspect you're referring to "engine braking" as Rotational_Acceleration,
whereas Jonny, Ruud, and Collin are referring to engine braking as Torque.  

  I see Jonny's point here too.  If you were to double the gear ratio, you'd
expect twice the acceleration out of the car (over some speed range at least).
However, this doesn't really wind up happening because the engine's
acceleration rate would have to double too, which takes torque in itself..  The
result?  Not as much torque left at the rear wheels...  Gotta run now, friend
just jumped up on my porch :0)

Todd Wasson
---
Performance Simulations
Drag Racing and Top Speed Prediction
Software
http://PerformanceSimulations.Com

My little car sim screenshots:
http://performancesimulations.com/scnshot4.htm

Doug Millike

A new demo of my simulator

by Doug Millike » Sun, 10 Feb 2002 12:39:01

I go away for a day and miss a physics slug fest!!
Box Score -- Modelers 1 (Ruud, Jonny), ex-racers 0 (rrevved), as I see it.

But no one yet has mentioned the magic words -- motoring torque.  It's hard
data to find, I don't have any that I can share for F1 or other racing
engines, sorry.

Steady-state motoring torque must be the sum of the torque due to friction
and pumping losses (actually "vacuum pumping", since the pistons are trying
to suck air through a closed throttle.) And a few other losses that could
be broken out like running the accessories (water/oil pumps, alternator,
etc.)

Note that race engines have a lot of valve overlap (assuming no variable
valve timing is used?), so at low rpm they are crappy pumps.

Motoring torque is measured on a powered dyno, where the engine under
test can be spun up to any rpm.  Them measure the torque required.  This
is most often done (afaik) when developing an automatic transmission
for a specific vehicle.

-- Doug Milliken

On Sat, 9 Feb 2002, Ruud van Gaal wrote:
> On Fri, 08 Feb 2002 14:20:01 -0600, rrevved <ed_b...@nope.com> wrote:

> >On Fri, 08 Feb 2002 14:25:57 GMT, r...@marketgraph.nl (Ruud van Gaal) wrote:
> ...
> >>Still, I'd think an F1 car will use a much lower inertia (less
> >>weighing flywheel) to be more responsive. Although ofcourse a higher
> >>inertia gives you a more stable accelerating/braking car.

> >Correct. And that's why engine braking is MUCH higher on any racing
> >car than a street car. Have you ever driven a purpose built racecar?

> Nope, sorry to say that I haven't.

> >In case you haven't, when you close the throttle into a corner,
> >you get much more natural (engine) braking than a street car.
> >A LOT more. It changes the handling of the car dramatically.

> Ok, so then it seems both the engine inertia is lower, AND the engine
> is fighting (giving negative torque) more than in a streetcar.

> >The reason is the lightened driveline components as well as the
> >generally lower gearing of the gearbox.

> The lower gearing is a secondary effect though and has nothing to do
> with the engine wanting to brake itself. The thing is I'm not looking
> for a net effect, since if some mysterious power was rotating the
> wheels, the engine wouldn't brake anyway, and you'd think engine
> braking torque was 0, which it isn't; it's just counterbalanced.

> So forget everything behind the engine and flywheel. Uptill there it's
> an autonomous system and should be viewed as such to look at 'engine
> braking'. Keeping the car in neutral or with the clutch applied, for
> example.

> > But forget the gearbox
> >for a second.

> Oh, yes, right. :)

> > That racecar will slow very quickly, without any
> >brakes whatsoever versus a street car. I'm talking about a
> >purpose-built race car here. F1/F3/Sprint Cars/Nascar/ CART, etc..
> >They all use lightened flywheels. They all will slow down much
> >quicker than a street car.

> Ok, then probably, with your experience, given a 0.74 coefficient for
> an F1 car, a street car might end up more like half of that (instead
> of being more).

> >As I said, just listen to the cars in the paddock. That should be
> >enough proof that the engines slow down very quickly when the
> >throttle is suddenly closed after being blipped. There are no
> >aerodynamics or torque or wings or anything else when they
> >do that. Just engine and flywheel.

> That's true.

> >>Did you drive it at LeMans back then? Would be way cool. :)

> >Graham Hill drove it at LeMans in 1956, I got it in about 1970
> >and raced SCCA with it. Chassis number 247.

> Must have been awesome. :)

> >I sold it in about 1975 because I'm stupid ..:)

> Ouch! ;-)

> >>I think that's more to do with the low INERTIA of the components,
> >>rather than the high braking coefficient (which just gives you the
> >>torque with which the engine is trying to slow down, not the actual
> >>speed at which this finally happens, since that is related to inertia
> >>as well).

> >Correct. Guess what causes inertia? You need an object
> >which has weight and a force which puts it in motion. The result
> >is a certain amount of inertia.

> Not at all; inertia is a fixed property of an object, just like mass.
> Nothing 'causes' inertia; it's there because the thing has
> molecules/mass.
> Like F=m*a, T=I*w where T=torque, I=inertia, w=angular acceleration.
> Mass is a constant property of an object, just like inertia (rather
> the inertia matrix).

> > If the object is lightweight, there
> >isn't as much inertia as with a heavy object.

> Right, but the inertia of the object remains fixed; it's the torque
> that changes (the engine pushing or pulling rotationally), and the
> angular acceleration is a result of that (w=T/I).

> >>F1 engines must be powerful to push the cars through the aero drag,
> >>even with high wing settings. So a massive engine braking contradicts
> >>that goal, since at high RPM the engine braking would really fight the
> >>engine from generating any torque to push the car forward through the
> >>air.

> >When the throttle is closed on any car, it isn't 'pushing'
> >anything.

> Surely the engine is pushing the drivetrain in the reverse direction
> of which it (the engine/drivetrain) is rotating in. Otherwise it
> wouldn't decelerate. So the engine is torqueing the drivetrain, no
> doubt in my mind.

> > Drag and inertia decide what happens, not power.

> Power is just a measurement of energy and is just a nice statistic,
> drag and inertia are inputs, yes.

> >>So I'd think striving for less engine braking would be beneficial
> >>for an F1 car; at high speeds you depend on the aero downforce and
> >>brakes to get good braking, instead of using the engine as a brake.

> >Nope. The purpose of low inertia driveline components
> >is for weight reduction, acceleration enhancement and braking
> >improvements. I'm surprised you don't know this.

> Didn't know about the braking improvements, but that surely does make
> sense. It seems though the downforce and brakes are most important,
> since the downforce generates implicitly the maximum longitudinal
> braking force you can apply to the car without locking the wheels. I'd
> say the brakes of an F1 car are powerful enough at any speed to lock
> the wheels, so in that sense, engine braking is of no importance for
> the total amount of braking you can apply to the tarmac; the limit is
> easily reached by the brakes alone, so engine braking just gets you
> there faster.
> But I may be completely off there, and F1 brakes may be impossible to
> lock at high speeds (but I don't think so).

> >With your theory, a racecar would be better off with
> >heavy driveline components, which of course is not the
> >way it is done.

> Hm, it's getting late. Have to rethink that. Indeed, less
> flywheel/engine inertia gives better deceleration. In my perspective,
> it's probably that the brakes can overcome the flywheel inertia as
> part of their job, so at a certain point you don't need a lighter
> flywheel.
> But I guess then maybe the wheel brakes aren't capable of locking the
> drivetrain at 300 km/h? Otherwise they could brake both the wheels and
> the engine, so the flywheel wanting to spin on wouldn't make that much
> of a difference.

> >>  engineAcceleration=engineTorque/engineInertia

> >Ruud, guess what causes that inertia? One -major- thing is the
> >flywheel.

> Right, that and the engine parts themselves.

> >>Nope, they're completely separate. I define the engine braking
> >>coefficient as being a measure of compression braking, and any
> >>friction in the engine. I don't try to include any other implicit
> >>effects.

> >You should.

> >Lightened flywheel/driveline is a MAJOR performance
> >consideration in a racecar. They actually drive totally
> >differently.

> It's in there; my engine inertia includes both flywheel and engine
> parts themselves (they are summed). The rest of the drivetrain
> ofcourse also has inertia and can be tweaked in every which way.

> The inertia just doesn't come into play until there's a torque from
> the engine and you want to know how fast all the parts in the
> drivetrain are going to accelerate (which is done in 2 parts in my
> sim; preclutch and postclutch; they can rotate at different speeds,
> which I need because I have an analog clutch simulated).

> Interesting chat, haven't written this much stuff in a post for some
> time. :)

> Ruud van Gaal
> Free car sim: http://www.racer.nl/
> Pencil art  : http://www.marketgraph.nl/gallery/

Dave Henri

A new demo of my simulator

by Dave Henri » Sun, 10 Feb 2002 14:50:13

  StopIT!  You guys are making my head hurt just BYPASSING these threads....
dave henrie

Gunnar Horrigm

A new demo of my simulator

by Gunnar Horrigm » Sun, 10 Feb 2002 22:01:23





> >> There are 2 parameters that decide the speed of revving up and down
> >> (in neutral); the engine torque (which includes engine braking and
> >> positive torque when the throttle pedal is pressed), and the engine
> >> inertia.

> >hm.  I always thought engine output and engine braking were completely
> >separate.  engine braking is, like you say, just mass, while power
> >output decreases with increasing mass.

> Uhm, engine braking is not mass, but torque, as I see it. The net
> torque an engine can produce is the sum of the part that make it want
> to accelerate (fuel burning), and the part that wants to brake it
> (pistons/air being compressed).

of course engine braking is torque, but I always thought that almost
_all_ of this was from inertia.  take two-strokes as an example, they
have insane compression ratios and virtually zero engine braking.

it's basically one of those simplex-clutches I can't remember what are
called.  very common on bikes.

--
Gunnar
    #31 SUCKS#015 Tupperware MC#002 DoD#0x1B DoDRT#003 DoD:CT#4,8 Kibo: 2
                             gitaren er en sjingke

Gunnar Horrigm

A new demo of my simulator

by Gunnar Horrigm » Sun, 10 Feb 2002 22:07:46


so a (lot) heavier flywheel will _not_ increase engine braking?
anyone know of any (simple) texts on this subject?  engine mechanics
for dummies or somesuch? :)

hm.  ok.  that helped somewhat.

--
Gunnar
    #31 SUCKS#015 Tupperware MC#002 DoD#0x1B DoDRT#003 DoD:CT#4,8 Kibo: 2
             "a poster is a human being or the software equivalent"

Gunnar Horrigm

A new demo of my simulator

by Gunnar Horrigm » Sun, 10 Feb 2002 22:14:50


I'm having serious problems with this.  a heavier flywheel makes for
lower engine braking?  that doesn't make sense to me...

fuel is burning even when the throttle is closed.

--
Gunnar
    #31 SUCKS#015 Tupperware MC#002 DoD#0x1B DoDRT#003 DoD:CT#4,8 Kibo: 2
        gnus don't kill people.  gnus-summary-lower-score kills people.

Gunnar Horrigm

A new demo of my simulator

by Gunnar Horrigm » Sun, 10 Feb 2002 22:26:12


oh aha.  I get it.  in my head "engine braking" has always been "the
rate at which the vehicle slows down" minus brakes and aero drag.  oh well.

--
Gunnar
    #31 SUCKS#015 Tupperware MC#002 DoD#0x1B DoDRT#003 DoD:CT#4,8 Kibo: 2
                                silence is FOO!

Gunnar Horrigm

A new demo of my simulator

by Gunnar Horrigm » Sun, 10 Feb 2002 22:22:19





> >> >ie: I would think that engine braking on a modern F1 car
> >> >is MASSIVE. Very light driveline components, high
> >> >compression, ratios, higher-revs/lower gearing etc.
> >> >would make them slow down REALLY fast when the throttle
> >> >is closed. You can hear this by listening to the revving
> >> >of their engines while in the paddock. When the throttle
> >> >is opened and then closed, they slow down REAL quick.
> >> >Much quicker than ... a Toyota Celica.

> >> Yeah. When Tiff Needell tested the Jaguar R1 he said(paraphrased) that
> >> letting off the throttle was like slamming the brakes on any normal
> >> car, slamming the brakes on the F1 was like hitting a brick wall. :)

> Yep to the above. Hell it was even strong in my old Lotus.

> >well, yeah.  I read somewhere that an F1 car at 200 kph will
> >decellerate at about 1 G if you just press the clutch.

> I bet if you read that again, it would say that an F1 car
> will decelerate at +1G if you- close the throttle- at 200K

maybe, but in that case whoever wrote it, should do a write up, as he
offered aerodynamic drag as the explanation. :)

--
Gunnar
    #31 SUCKS#015 Tupperware MC#002 DoD#0x1B DoDRT#003 DoD:CT#4,8 Kibo: 2
             "a poster is a human being or the software equivalent"

na_bike

A new demo of my simulator

by na_bike » Sun, 10 Feb 2002 23:15:53




>> you can indeed see that higher (flywheel+engine parts) mass, or rather
>> inertia means engineInertia goes up, so engineAcceleration goes down.
>> Which is lower engine braking.

>I'm having serious problems with this.  a heavier flywheel makes for
>lower engine braking?  that doesn't make sense to me...

Think of it this way:

The [heavier]flywheel means more inertia, more inertia means that the
engine is less "willing" to rev down, i.e. it "wants" to keep it's
speed.

If you had a 500kg flywheel like in some old steamengines all braking
power would go to braking the _flywheel_....

Colin Re

A new demo of my simulator

by Colin Re » Sun, 10 Feb 2002 23:18:50


it should not have been producing -700Nm of -ve engine torque at
7000rpm ;-)

Colin

Gunnar Horrigm

A new demo of my simulator

by Gunnar Horrigm » Mon, 11 Feb 2002 01:22:14





> >> you can indeed see that higher (flywheel+engine parts) mass, or rather
> >> inertia means engineInertia goes up, so engineAcceleration goes down.
> >> Which is lower engine braking.

> >I'm having serious problems with this.  a heavier flywheel makes for
> >lower engine braking?  that doesn't make sense to me...

> Think of it this way:

> The [heavier]flywheel means more inertia, more inertia means that the
> engine is less "willing" to rev down, i.e. it "wants" to keep it's
> speed.

but that _is_ the way I'm thinking.  and since it "wants" to keep it's
speed it has _more_ engine braking.

where I come from, the flywheel is an engine part. :)

anyway; I've figured it out.  you guys are just talking about the
engine, while I was thinking of the vehicle as a whole.

--
Gunnar
    #31 SUCKS#015 Tupperware MC#002 DoD#0x1B DoDRT#003 DoD:CT#4,8 Kibo: 2
                 "Det er nok ingen ovn, men fartsm?leren v?r."

Byron Forbe

A new demo of my simulator

by Byron Forbe » Mon, 11 Feb 2002 02:14:49



> >   I'm afraid he's exactly right, rrevved.  I think you may not be aware that
> > Jonny is speaking of two different things seperately here, where it sounds like
> > you might be combining them in one concept, although mathematically, they are
> > seperate things.  The steady state torque the engine produces has nothing to do
> > with the mass of the engine.

> so a (lot) heavier flywheel will _not_ increase engine braking?
> anyone know of any (simple) texts on this subject?  engine mechanics
> for dummies or somesuch? :)

   Just the opposite! In fact, as far as engine "braking" is concerned,
the engine sees no difference between the mass of itself (it's internal
parts, it's external parts eg - flywheel) or the mass of the car,
wheels, etc. It's all just one big mass!

    F = MA

  Force = Braking, Mass = Mass of (car + wheel inertia + engine +
inertia of engine bits)

  Question is, what causes acceleration/decelleration ie change in
speed/rpm?

  Answer = friction + (compression/heat loss and pressure drops)

      friction is obvious and insignificant?

      Looking at 1 cylinder and it's 4 strokes -

         Intake = low pressure (Closed throttle - Vacuum) ie small force
on top of cylinder (very small +)
         Exhaust = Virtually 1 atmosphere greater than intake (-)
         Compression = Obvious + we have heat loss we do not get back on
combustion stroke ie loss of energy from a non elastic event. (-)
         Combustion - finally the engine momentum gets some substantial help
:)) (+)

    Now lets get right down into the nitty gritty! LOL

   As rpm increases  Intake = virtual Vacuum ie zero effect
                     Exhaust = greater piston speed -> greater pressure
                     Compression - same as exhaust
                     Combustion - Hmmm, let's see. Can the gasses, ignited ATDC?, ever
catch up with a piston accelerating away at maybe 10,000 + RPM? ie
diminishing effect in forward direction.

     Conclusion - as we raise rpm at idle throttle settings we increase
"engine braking"! Commonly referred to on the streets as "compression
lockup"!

   Glad I got that off my chest. Now I'm back off to the nut house for
another couple of years :))

Byron Forbe

A new demo of my simulator

by Byron Forbe » Mon, 11 Feb 2002 02:46:12

   Well, you are/were actually right and wrong both times :)

  Drag is proportional to speed under slipstreamed conditions.

  Drag is proportional to the square of speed in turbulent conditions.

  The speed at which slipstream airflow degenerates into turbulent
airflow will vary for all the different bits of said car!



> > Second hint: a Celica has perhaps 100 hp, and a top speed of
> > perhaps 120 mph.  The F1 has 800 hp and a top end of 210 mph.

> > Aero power requirements rise with the cube of speed.

> > (120^3 / 100^3)^0.33 = 1.2 (~= mph / hp)

> > (210^3 / 800^3)^0.33 = 0.26.  IOW, the Celica is getting far
> > more maximum speed per horsepower than the F1 car - which suggests
> > it has just a tiny bit less drag.

> Okay, I'll try that again without cubing the power.  (See, Todd,
> I told you you should never trust my equations - especially this
> late at night!)

> P = k1 * drag * speed^3
> drag = k2 * P / speed^3

> For the Celica, that gives drag of 100 / 120^3 = 0.000 057 8 [units]
> For the F1, it's 800 / 210^3 = 0.000 086 4 [units].

> Not a huge difference - the F1 is smaller but has a higher Cd
> - but still the same way round.

> Jonny
> proving that you *can* get a decent degree without being able
> to get the right answer first time...

Goy Larse

A new demo of my simulator

by Goy Larse » Mon, 11 Feb 2002 02:56:28


>    Glad I got that off my chest. Now I'm back off to the nut house for
> another couple of years :))

Not a single personal insult to be found anywhere, I'm slightly
disappointed, impressed in one way, but also disappointed, you haven't
gotten old on us have you Byron ?

Beers and cheers
(uncle) Goy

"The Pits"    http://www.theuspits.com/

* Spam is for losers who can't get business any other way *
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