This isn't quite right. Friction force is not constant, but depends on the
weight of the car. Lets call if Fr:
Fr = u*N , where N is the the force the car presses on the surface (the
weight of the car) and u is a constant depending of the tire and the surface
(don't know what it is called in English, but direct translation from the
Finnish term would be "friction factor").
N = m*g when the car is on horizontal surface (ie. direction of gravity is
perpendicular to the surface). This gives:
Fr = u*m*g , so the force is directly related to the weight (and mass) of car.
Actually, this is not the real friction force, but is the maximum possible
force engine can use to accelerate the car before wheel spin occurs (well,
in fact wheel spin occurs much earlier, because only the rear wheels are
accelerating the car, so N should be te part of the cars weight which is
distributed on the rear wheels... To make it more complicated, this will
change when the car accelerates...)
Fr is the limiting factor only when the car is accelerating at a slow speed
(as in the start or after a slow corner for example). At these situations,
the weight of the car has no effect on the acceleration:
a = Fr/m
a = u*m*g/m
a = u*g , so at these situations, the acceleration is only affected by
friction factor and g (acceleration caused by gravitation).
This is of course when the driver is not spinning wheels.
But, when the force engine can generate stays below Fr, a car with less fuel
(and thus with less mass) will accelerate faster:
a = F/m , F is the force generated by engine, and m is the mass of the car.
As F doesn't depend on the weight or mass of the car (depends on rev and gear,
can be considered constant in this calculation), lighter car accelerates
more quickly at speeds where Fr is no longer the limiting factor.
Aerodynamics affect these figures quite a lot, especially at higher speeds,
causing the increase of N and Fr (downforce), and loss of acceleration
(negative force due to drag). However, it has nothing to do with the fact
that lighter car accelerates more quickly.
To sum this up, there is no need to simulate gravity to make the car accelerate
differently depending on fuel load.
I hope I make some sense,
Samppa
--
Samuli Takala, Pajamaentie 14 C 38, 00360 Helsinki | "Ron Dennis smiled like
URL: http://www.hut.fi/~tax/ (soon) | -- Matti Kyllonen