rec.autos.simulators

physics question

Sébastien Tixie

physics question

by Sébastien Tixie » Wed, 24 Apr 2002 15:02:07

Waow, ;o)

Your explanations are really interesting however i can't see form wich
theoreme you get your equation ?

you mean coefficient of fiction or friction force here ? i would said
friction force.
Fritcion force F = k . Load.
If you mean the coeficient of friction, i didn't know that it was
variable with the load , i thought it was constant at constant
temperatures for a given couple material/surface.

hmm, i don't see where did you take this equation from ?
Could you explain me what's is 'a' in your equations.

Yes  this is something all setup's gurus know ;o)

Well, you have also to take account that when driving with lot of
sideways the rear wheel slip at lot more that the front wheel, so they
loose more lateral grip that the front making the car oversteer.

After thinking about that i think now that the more important effect
of driving sideway on slippy surface is to use the longitudinal forces
to couter act the centrigal forces.

regards,
Sebastien TIXIER - Game Developer
Dynamics and Car Physics
http://www.racesimcentral.net/
GPLRank Normal:-44.24   Monster:-124.44

Haqsa

physics question

by Haqsa » Thu, 25 Apr 2002 08:03:23

Not necessarily true.  Rear wheels slipping more than the front is by
definition oversteer, but a heavily understeering car can still be
driven at a very high yaw angle if it is allowed sufficient steering
lock.  Driving sideways does not necessarily mean oversteer, you have to
look at the front wheel angle also.


Dave Pollatse

physics question

by Dave Pollatse » Thu, 25 Apr 2002 09:39:42

As far as I know, all road tires have lower coefficients of friction at
higher load (tire load sensitivity).  If you don't have this effect in a
sim, your spring/swaybar adjustments won't have the expected result. (As I
discovered from experience! ;)
Here's an example from RCVD (Fig 2.30)
A P225/70 R15 at 0 camber angle has a coefficient of friction (Fy/Fz) about
1.0 at 200 lbs of load, and 0.9 at 1600 lbs of load.
My little "ax + b" function was just a quick empirical fit to that type of
data (the graph is pretty close to linear, and anyways I was just trying to
establish in which direction the force changes)
So a 1.0G tire that didn't exhibit this would have a = 0, b = 1.0 in this
case, and the tire I mentioned above would have something like a = 0.1 /
(1600 - 200 lbs), b = 1.02 or so.

I'm imagining a simple tire model that looks something like
Mu = calc_mu(load) = a * load + b
tire_force = f(slip_angle) * Mu * load, where f(x) is one of those
nondimensional "magic formulae" that peaks at 1.0.
(My tire models used the nondimensional tire method as described in Chap 14
of RCVD as their starting point--so my notation may be nonstandard compared
to other methods)
Since we're talking about max cornering power, I'm assuming that all wheels
are at optimum slip angle, thus tire_force = Mu * load.

This could be written as
left_load * calc_mu(left_load) + right_load * calc_mu(right_load)
where left_load = (1 - t), right_load = (1 + t), where t is lateral weight
transfer fraction (I normalized everything by m*g just to make the math
easier)

I hope this clarifies things--sorry I'm not very good at using standard
notation, plus the fact that I tend to think in pounds and not newtons!  ;)

-Dave


Dave Henri

physics question

by Dave Henri » Thu, 25 Apr 2002 11:56:52

"Dave Pollatsek"
  Dave can I break into this "FACINATING" discussion and ask you to email me

btw..the only thing I know about tire models is they stand next to tires at
trade shows......right?
dave henrie


Doug Millike

physics question

by Doug Millike » Thu, 25 Apr 2002 11:39:22

For the pavement case, see RCVD Chapter 7 -- Pair Analysis, could
have saved you some typing<grin>.

As far as tire data on dirt, I think that most of the published work has
been done for/by the US Army Tank Automotive Command (TACOM) in Detroit,
just down the road from the GM Tech Center.  For many years they ran tire
tests on different kinds of prepared soil "bins" to study "land
locomotion".  The key guy (now dead) was named Bekker.
  Their data may not apply all that well to high speeds...

Other tire test rigs have been built onto trucks of various sorts, the big
problems might be instrumentation and getting repeatable data in some
coordinate system (when everything is bouncing around!)--so that the data
is usable.

-- Doug Milliken
   http://www.millikenresearch.com/olley.html  <-- new book!


> Sorry, I wasn't being very clear... by more grip I meant higher coefficient
> of friction, not actual friction force.  I guess what it boils down to is
> the behavior along an axle (let's assume a single-axle rally car for
> convenience on a flat road.)
> Let t be the fraction of lateral load transfer, then the normal forces at
> the wheels are
> mg*(1-t) and mg(1+t).  For simplicity, let's normalize everything to mg, so
> this becomes
> (1-t) and (1+t)
> Let the coeff of friction be a linear function of load, f(x) = ax + b, which
> will be accurate for these purposes since we're just looking at the behavior
> at a given load +/- a small delta.
> then the max lateral grip should be:
> (1-t)*f(1-t) + (1+t)*f(1+t) =
> uhmmmm.....   (really, I have a point here, bear with me.... ;)
> (1-t)*(a(1-t)+b) + (1+t)*(a(1+t)+b) =
> a-at+b - at + at^2 -bt + a + at + b + at + at^2 + bt =
> 2a + 2b + 2at^2 = 2(a + b + at^2)  (whew, stuff cancelled out!)
> So this shows that when "a" is negative (which is true of tires on asphalt,
> or at least of every tire data I've ever seen), the maximum cornerering
> force is at t=0, or no load transfer.  This, of course, explains why
> increasing front roll stiffness causes understeer and increasing rear roll
> stiffness causes oversteer: because the total grip at the stiffer end has
> more lateral load transfer, and thus loses more grip.
> So if on dirt, "a" would have to be positive to have the effect of lateral
> load transfer increasing grip, which would also have the effect of flipping
> the understeer/oversteer of a car, which is the behavior I'm having trouble
> with imagining or matching up to what I've seen.  I think I can imagine this
> being true for really wet tarmac, as you say, because increasing the load
> would decrease hydroplaning.   I suppose the same argument could be made for
> a tire on dirt making a "furrow" in the ground, this could cause a "digging
> in" effect, which could result in positive "a"...

> What we really need is a tire dyno for dirt.  I'm thinking of an old school
> bus driving down a dirt road with a tire mounted on an arm sticking off the
> side bolted to some bathroom scales... throw in some C-clamps and a lot of
> duct tape for good measure.  I'm still pretty sure that the peak is at a
> wide slip angle, although until one of us actually coughs up some real data,
> we're just ... (insert colorful aphorism of your choice here)

> -Dave P.
> PS.  I'm actually only *mostly* joking about the bus thing.  I just may try
> it some day... ;)



> > On Sat, 20 Apr 2002 17:00:39 -0500, "Dave Pollatsek"

> > >I'm guessing the "more load = more grip" thing, if true, is nonlinear; if
> it
> > >were strictly true, than this would mean that the load sensitivity is
> > >inverse to asphalt, which would imply that a typical RWD sedan (e.g., 55
> %
> > >front weight, same tires front and rear, more roll stiffness in front to
> > >make it "safely" understeer) would be oversteer on gravel, while an
> > >oversteer car would become understeer.

> > Well, no. In Asphalt you also have more lateral force with more load.
> > Just look at the pacejka formula. However that's true that for very
> > strong load the lateral force start to decrase.

> > >In my experience, production cars
> > >still understeer in loose surfaces unless the handbrake or some sort of
> > >throttle technique (left-foot brake on FWD, or dipping the clutch on RWD)
> is
> > >used to degrade rear grip.

> > That's true, the car always loose lateral force on the driven wheels
> > because those wheel tends to slip more.

> > >Also, I wouldn't expect removing ARBs to change steady-state total
> lateral
> > >load transfer--isn't that merely a function of lateral force, CG height,
> and
> > >track width?  I would, however, expect removing ARBs to reduce wheel-hop
> on
> > >bumpy surfaces.

> > Rally driver usually removes the ARB on wet tarmac because it's a
> > really slippy surfaces. Nothing to do with bumps. It's, again, to
> > increase the lateral load transfert.

> > >I think the biggest factor is that the friction peak on loose surfaces is
> at
> > >an extremely wide slip angle, probably due to a quasi-viscous behavior of
> > >dirt building up on the outside edge.  I think there's also some
> threshhold
> > >where for very tight turns, it's faster to rotate the car by sliding than
> to
> > >actually take the turn "properly"--hence autocrossers use the handbrake
> even
> > >on asphalt.
> > >Whatever is true, there's no doubt that there isn't enough stuff written
> > >about offroad tire behavior!!!

> > I think the optimum slip angle on slippy surfaces is tighter, because
> > the contact patch on loose surfaces has less friction
> > so it's deformation is smaller on slippy surface.

> > IMO, regards,

> > Sebastien TIXIER - Game Developer
> > Dynamics and Car Physics
> > http://www.eden-studios.fr
> > GPLRank Normal:-44.24 Monster:-124.44

Dave Pollatse

physics question

by Dave Pollatse » Thu, 25 Apr 2002 15:46:49

Thanks for the info!  I love the internet--two more clicks and a paper is on
the way (fif*** bucks lighter, of course)  It looks from my quick search
that people are using Bekker's model for things like ATVs and humvees, which
seems promising.

I know you must have done a far more elegant pair analysis than that pile of
dung I came up with, but I wanted to see if I could get the correct result
off the top of my head...
for the record, found a mostly unlabeled set of slides or something on the
Humvee.
If I'm reading the graphs right, lateral friction peaked at at least 30
degrees slip angle (that's where the graph stopped, but it looked pretty


I suppose the load sensitivity could be backwards when in the "digging"
mode--this disparity also suggests that you might be better off slowing down
by driving sideways, as lateral grip seemed higher across the board.  That
is, if one had a humvee to take to the track.
-Dave


For the pavement case, see RCVD Chapter 7 -- Pair Analysis, could
have saved you some typing<grin>.

As far as tire data on dirt, I think that most of the published work has
been done for/by the US Army Tank Automotive Command (TACOM) in Detroit,
just down the road from the GM Tech Center.  For many years they ran tire
tests on different kinds of prepared soil "bins" to study "land
locomotion".  The key guy (now dead) was named Bekker.
  Their data may not apply all that well to high speeds...

Other tire test rigs have been built onto trucks of various sorts, the big
problems might be instrumentation and getting repeatable data in some
coordinate system (when everything is bouncing around!)--so that the data
is usable.

-- Doug Milliken
   http://www.racesimcentral.net/;<-- new book!


> Sorry, I wasn't being very clear... by more grip I meant higher
coefficient
> of friction, not actual friction force.  I guess what it boils down to is
> the behavior along an axle (let's assume a single-axle rally car for
> convenience on a flat road.)
> Let t be the fraction of lateral load transfer, then the normal forces at
> the wheels are
> mg*(1-t) and mg(1+t).  For simplicity, let's normalize everything to mg,
so
> this becomes
> (1-t) and (1+t)
> Let the coeff of friction be a linear function of load, f(x) = ax + b,
which
> will be accurate for these purposes since we're just looking at the
behavior
> at a given load +/- a small delta.
> then the max lateral grip should be:
> (1-t)*f(1-t) + (1+t)*f(1+t) =
> uhmmmm.....   (really, I have a point here, bear with me.... ;)
> (1-t)*(a(1-t)+b) + (1+t)*(a(1+t)+b) =
> a-at+b - at + at^2 -bt + a + at + b + at + at^2 + bt =
> 2a + 2b + 2at^2 = 2(a + b + at^2)  (whew, stuff cancelled out!)
> So this shows that when "a" is negative (which is true of tires on
asphalt,
> or at least of every tire data I've ever seen), the maximum cornerering
> force is at t=0, or no load transfer.  This, of course, explains why
> increasing front roll stiffness causes understeer and increasing rear roll
> stiffness causes oversteer: because the total grip at the stiffer end has
> more lateral load transfer, and thus loses more grip.
> So if on dirt, "a" would have to be positive to have the effect of lateral
> load transfer increasing grip, which would also have the effect of
flipping
> the understeer/oversteer of a car, which is the behavior I'm having
trouble
> with imagining or matching up to what I've seen.  I think I can imagine
this
> being true for really wet tarmac, as you say, because increasing the load
> would decrease hydroplaning.   I suppose the same argument could be made
for
> a tire on dirt making a "furrow" in the ground, this could cause a
"digging
> in" effect, which could result in positive "a"...

> What we really need is a tire dyno for dirt.  I'm thinking of an old
school
> bus driving down a dirt road with a tire mounted on an arm sticking off
the
> side bolted to some bathroom scales... throw in some C-clamps and a lot of
> duct tape for good measure.  I'm still pretty sure that the peak is at a
> wide slip angle, although until one of us actually coughs up some real
data,
> we're just ... (insert colorful aphorism of your choice here)

> -Dave P.
> PS.  I'm actually only *mostly* joking about the bus thing.  I just may
try
> it some day... ;)



> > On Sat, 20 Apr 2002 17:00:39 -0500, "Dave Pollatsek"

> > >I'm guessing the "more load = more grip" thing, if true, is nonlinear;
if
> it
> > >were strictly true, than this would mean that the load sensitivity is
> > >inverse to asphalt, which would imply that a typical RWD sedan (e.g.,
55
> %
> > >front weight, same tires front and rear, more roll stiffness in front
to
> > >make it "safely" understeer) would be oversteer on gravel, while an
> > >oversteer car would become understeer.

> > Well, no. In Asphalt you also have more lateral force with more load.
> > Just look at the pacejka formula. However that's true that for very
> > strong load the lateral force start to decrase.

> > >In my experience, production cars
> > >still understeer in loose surfaces unless the handbrake or some sort of
> > >throttle technique (left-foot brake on FWD, or dipping the clutch on
RWD)
> is
> > >used to degrade rear grip.

> > That's true, the car always loose lateral force on the driven wheels
> > because those wheel tends to slip more.

> > >Also, I wouldn't expect removing ARBs to change steady-state total
> lateral
> > >load transfer--isn't that merely a function of lateral force, CG
height,
> and
> > >track width?  I would, however, expect removing ARBs to reduce
wheel-hop
> on
> > >bumpy surfaces.

> > Rally driver usually removes the ARB on wet tarmac because it's a
> > really slippy surfaces. Nothing to do with bumps. It's, again, to
> > increase the lateral load transfert.

> > >I think the biggest factor is that the friction peak on loose surfaces
is
> at
> > >an extremely wide slip angle, probably due to a quasi-viscous behavior
of
> > >dirt building up on the outside edge.  I think there's also some
> threshhold
> > >where for very tight turns, it's faster to rotate the car by sliding
than
> to
> > >actually take the turn "properly"--hence autocrossers use the handbrake
> even
> > >on asphalt.
> > >Whatever is true, there's no doubt that there isn't enough stuff
written
> > >about offroad tire behavior!!!

> > I think the optimum slip angle on slippy surfaces is tighter, because
> > the contact patch on loose surfaces has less friction
> > so it's deformation is smaller on slippy surface.

> > IMO, regards,

> > Sebastien TIXIER - Game Developer
> > Dynamics and Car Physics
> > http://www.racesimcentral.net/
> > GPLRank Normal:-44.24 Monster:-124.44

Jonny Hodgso

physics question

by Jonny Hodgso » Fri, 26 Apr 2002 05:33:53


> Lateral weight transfer can be increased slightly by removing bars
> because the roll angle will increase, and rally cars have a fairly high
> CG, therefore the CG and its acceleration vector are going to point

Valid point, forgot about that one.

... or at least, the load transfer will happen more gradually and is
therefore less likely to upset the tyres and trigger a slide.

Indeed - although recently I've taken to running ARBs both ends
together with soft springs, to keep my 1/10th off-roader shiny side
up on my (rather bumpy) local track.  Could just be the above-mentioned
transient behaviour, though, encouraging it to slide when it catches
a pothole rather than grip-rolling ;-)

Jonny


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