Hi Sebastien,
Starting with the formula you presented (F = k v ) is a very good
approximation, and, depending on how far you want to go with it, should
perhaps be just sufficient (I have a feeling GPL and N4 don't use
anything else).
Generally, however, you would have
F=F(v),
and a good approximation for many a damper is to have a function
F = k1 v for |v|< v0
and
F = k2 * (v - v0) + k1 * v0 for v > v0
and
F = k2 * (v + v0) - k1 * v0 for v <-v0
where |k2| < |k1|, since at a certain speed, as you mention, additional
valves may open (in GP3, for example, the coefficients k1 and k2 are low
and high speed dampers, respectviely). The function F is therefore a
line with kinks into shallower lines at |v|=v0
To get an estimate for the dampening required for any kind of a car,
assume that each part carries about an equal weight (the total mass of
the car being M), and four springs, all with the coefficient K. If you
look at the differential equation that governs the total up/down car
movement,
M x'' + 4 k1 x' + 4 K = 0 ,
the optimal damping will be achieved when
k = sqrt( M * K ) .
Start with this and then tweak to reach a good setup.
-Gregor
> Hi !
> If we simplify a force damper is
> F = k * v
> v = damper piston velocity
> k = damper oil viscosity coefficient ( k<0 )
> Do somebody have an idea of k value for a stock car damper ????
> In reality k = F( v ), because on the piston there are some valves that
> opens when v incerase
> Do somebody have this function ?
> Can't find those infos at Ohlins web site or anywhere :o(
> regards,
> --
> Seb -
> Game Developer
> http://www.eden-studios.fr
> GPLRank -41.68
> http://magicfr.multimania.com