Given speed and distance figures comming in at the rate of fif***
samplings per second, how do I compute the acceleration?
--
Chuck Stuart - Mesquite TX USA
Given speed and distance figures comming in at the rate of fif***
samplings per second, how do I compute the acceleration?
--
Chuck Stuart - Mesquite TX USA
>--
>Chuck Stuart - Mesquite TX USA
accel (fps) = (S - S ) * 15
n n-1
Where S is your speed samples. You don't need the distance samples if your
speed samples are accurate.
Dave (davids) Sparks
Late Night League
http://www.racesimcentral.net/
The calculation for acceleration between two consecutive velocity points,
v1 and v2, is as follows:
a = (v2 - v1) / (1/15)
You don't need the distance figures because acceleration is simply a
derivative of velocity over time.
Lawrence Lo
> --
> Chuck Stuart - Mesquite TX USA
last I knew, aceleration (medium) was a= (v2-v1) / (t2-t1) .
The aceleration (instantaneous) is a= lim (v2-v1) / (t2-t1) when
(t2-t1) tends to 0. I don't know how the written simbol is but
normally (v2-v1) is represented by /\t (with a base line)
I don't know a lot of physics so I maybe wrong but I doubt it, since
it's was it taught everywhere else in the world.
...:-=>> The freaking Mail Band <<=-:...
http://www.geocities.com/MotorCity/3039
>>--
>>Chuck Stuart - Mesquite TX USA
>Try this:
>accel (fps) = (S - S ) * 15
> n n-1
>Where S is your speed samples. You don't need the distance samples if your
>speed samples are accurate.
accel = (S[n] - S[n-1]) * 15 ft / (sec**2)
Where S is the vector of speed samples and n is the index.
Dave (davids) Sparks
Late Night League
http://www.racesimcentral.net/
>>You don't need the distance figures because acceleration is simply a
>>derivative of velocity over time.
>last I knew, aceleration (medium) was a= (v2-v1) / (t2-t1) .
>The aceleration (instantaneous) is a= lim (v2-v1) / (t2-t1) when
>(t2-t1) tends to 0. I don't know how the written simbol is but
>normally (v2-v1) is represented by /\t (with a base line)
Everything posted to this point has been correct, just different
interpretations of the same equation. 1/15 is the same as delta t in this
case because the data is given 15 times/s, so each set of data is 1/15th of
a second apart.
Gregory Fung
Vancouver, B.C., Canada
IICC3 Rebel Alliance Lola/Ford/Firestone
ITCC Player's Ltd. Audi A4
why do you multiply it by 15 ?? i don't know that formula.
...:-=>> The freaking Mail Band <<=-:...
http://www.geocities.com/MotorCity/3039
>>Where S is your speed samples. You don't need the distance samples if your
>>speed samples are accurate.
>why do you multiply it by 15 ?? i don't know that formula.
you know a=v/t, there you go.
Gregory Fung
Vancouver, B.C., Canada
IICC3 Rebel Alliance Lola/Ford/Firestone
ITCC Player's Ltd. Audi A4